Hi I am looking to fuse on the DC side a 1500 PSW Inverter running small items ie tv,mobile phone charging, electric bike charging, laptop .Is there a formula for working out the size of fuse. All help appreciated. Robert.
Fuses are fitted to protect the cable from overload / overheating.. so the fuse size should be calculated to the max safe full load current of the cable..
A 1500 watt inverter on full load will draw: w/v = 1500/12 = 125A
do you know what size the cable is .. ?
are you using what has been supplied or fitting your own ?
and if so what is the length ?
For example.. if your cable run is 1 mt you will need 25mm cable (acceptable loss of 2%)
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.