I understand that if i have a 1500w inverter it will draw at full tilt around 125amps 1500/12 = 125, i think.
So does that mean if i ran it for an hour(which i am not going to do) it would draw 125 amps, but more importantly if i run it for 10 mins it will use 125/60*10 = 21 amps rounded up ?
I have a am sealed 150amp battery that i want to use the inverter with hence the question.
Changing the battery for something more powerful would involve moving them to back of van which i don't really want to do. Hence the question
Karl
So does that mean if i ran it for an hour(which i am not going to do) it would draw 125 amps, but more importantly if i run it for 10 mins it will use 125/60*10 = 21 amps rounded up ?
I have a am sealed 150amp battery that i want to use the inverter with hence the question.
Changing the battery for something more powerful would involve moving them to back of van which i don't really want to do. Hence the question
Karl