Alicia
Free Member
So we are kitting out out MH and thinking of a 12v kettle- do they suck the life out of your leisure battery?? Is it worth it for a cuppa or shall I just go straight to wine??!
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Of itvwas on arrival it was probably 24volt not 12My pal had a 12v jobby in his truck that plugged into cigarette lighter. Was fairly quick when I went out with him once
I only drink coffee ... But I'd use gas anyway in our Brunhilde which is our wee ohm from ohm ... Steve, proving again that what he knows about physics plus tuppence would be insufficient to purchase a penny bun ...Some O-level sums, if you're old enough to remember them...
2 mugs of tea is about 500ml. The energy required to heat 500ml of water from 20C to 100C is 500x80 calories, or about 160kJ. This is the only important number - it doesn't matter if you're running from 12V or 240V, or anything else, so ignore the previous comment about using an inverter (in fact, you need maybe 10% more energy if you're running off an inverter). 160kJ is about 3.7Ah, if you prefer Ah (you shouldn't, they're pretty useless).
So can you get 160kJ out of a leisure battery, in a relatively short time, without causing problems? Start with the power consumption of your kettle. 12V kettles seem to come with heating elements of about 100W to 150W, judging from what's on amazon. You need as much power as possible, so say 150W. 160,000/150 = 1067s, or about 18 minutes. So you can boil 2 mugs of water in about 18 minutes with a powerful 12V kettle. If you do have an inverter, and you can find a mains kettle which has a power rating (significantly) below the power rating of your inverter, you could get your tea quicker (but this doesn't use less energy overall). It looks like you can buy "low power" mains kettles at 750W (so you'd need a 1kW inverter, which is expensive). This will boil your water in 160,000/750 = 3.5 minutes.
To find the current required from the battery, the worst-cast scenario is the 750W kettle (say 850W after taking into account losses). A 12V battery has to provide 70A (for 3.5 minutes) in this case. Should be Ok, but I wouldn't do it. For the 150W 12V kettle, the battery has to supply 12.5A for 18 minutes, which is Ok.
In either case, you're taking 3.7Ah out of a battery which has maybe 100-120Ah capacity. If you've got lead acid, then the available capacity is much less, of course, and you're probably taking 10% of the usable stored charge just for 2 mugs of tea.
In short, use spirit or gas, unless you've got lots of solar hanging around doing nothing.
OK, if you had put your 12v kettle on when you posted you would be pouring the tea about now! But, would have a flat battery!So we are kitting out out MH and thinking of a 12v kettle- do they suck the life out of your leisure battery?? Is it worth it for a cuppa or shall I just go straight to wine??!
But the flat battery would enable me to close the compartment lid ... I'm sure I read about it on one of those lithium threadsOK, if you had put your 12v kettle on when you posted you would be pouring the tea about now! But, would have a flat battery!
I'm growing old, took me a few minutes to get that.But the flat battery would enable me to close the compartment lid ... I'm sure I read about it on one of those lithium threads
Steve
I have been through the numbers using specific heat capacity of water as 4.2J/kg/K and get to 168kJ so close enough to your number, I then took this to 46.6 watt/hour which you could easily call 50 Wh with a few losses from the kettle and an inverter if going that way, so 50Wx60 = 3kw kettle for 1 minute would do the job or put another way 3000/750 for your low power kettle = 4 minutes so again not far away from your 3.5 minutes.Some O-level sums, if you're old enough to remember them...
2 mugs of tea is about 500ml. The energy required to heat 500ml of water from 20C to 100C is 500x80 calories, or about 160kJ. This is the only important number - it doesn't matter if you're running from 12V or 240V, or anything else, so ignore the previous comment about using an inverter (in fact, you need maybe 10% more energy if you're running off an inverter). 160kJ is about 3.7Ah, if you prefer Ah (you shouldn't, they're pretty useless).
So can you get 160kJ out of a leisure battery, in a relatively short time, without causing problems? Start with the power consumption of your kettle. 12V kettles seem to come with heating elements of about 100W to 150W, judging from what's on amazon. You need as much power as possible, so say 150W. 160,000/150 = 1067s, or about 18 minutes. So you can boil 2 mugs of water in about 18 minutes with a powerful 12V kettle. If you do have an inverter, and you can find a mains kettle which has a power rating (significantly) below the power rating of your inverter, you could get your tea quicker (but this doesn't use less energy overall). It looks like you can buy "low power" mains kettles at 750W (so you'd need a 1kW inverter, which is expensive). This will boil your water in 160,000/750 = 3.5 minutes.
To find the current required from the battery, the worst-cast scenario is the 750W kettle (say 850W after taking into account losses). A 12V battery has to provide 70A (for 3.5 minutes) in this case. Should be Ok, but I wouldn't do it. For the 150W 12V kettle, the battery has to supply 12.5A for 18 minutes, which is Ok.
In either case, you're taking 3.7Ah out of a battery which has maybe 100-120Ah capacity. If you've got lead acid, then the available capacity is much less, of course, and you're probably taking 10% of the usable stored charge just for 2 mugs of tea.
In short, use spirit or gas, unless you've got lots of solar hanging around doing nothing.
Depends what time you have breakfast.With breakfast?