I would appreciate some guidance on my logic of calculating inverter usage.
So here is an example of my logic.
I have a sterling 300W pure sine wave inverter which states :
No load Quiescent current 0.95A (I take this to mean when switched on it draws 0.95A an hour from my leisure batteries.
I also have a 240 V plug to charge a device and on that plug it states input 100-240V -50/60Hz -500mA Output 12.0V -1600mA.
Would I be correct in assuming that if I plug this device into my Inverter and switch it on the total draw from my leisure batteries would be.
0.95 + 1.6 =2.55 Amps per hour.
Thanks in advance.
So here is an example of my logic.
I have a sterling 300W pure sine wave inverter which states :
No load Quiescent current 0.95A (I take this to mean when switched on it draws 0.95A an hour from my leisure batteries.
I also have a 240 V plug to charge a device and on that plug it states input 100-240V -50/60Hz -500mA Output 12.0V -1600mA.
Would I be correct in assuming that if I plug this device into my Inverter and switch it on the total draw from my leisure batteries would be.
0.95 + 1.6 =2.55 Amps per hour.
Thanks in advance.